2x^2/3-7x^1/3+3=0

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Solution for 2x^2/3-7x^1/3+3=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-((7*x^1)/3)+3 = 0

(2*x^2)/3+(-7/3)*x+3 = 0

2/3*x^2-7/3*x+3 = 0

DELTA = (-7/3)^2-(2/3*3*4)

DELTA = -23/9

DELTA < 0

x belongs to the empty set

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